What are the solutions to the equation -2x(3x-2)=-2 ?

The solutions to the equation -2x(3x-2)=-2 are x=-1/3 ,x=1

Find the zeros of -2x(3x-2)=-2

The zeros of -2x(3x-2)=-2 are x=-1/3 ,x=1

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- 2 x (3 x - 2) = - 2

x = - \frac{1}{3}, x = 1

Decimal

x = - 0.33333 \dots, x = 1

Solution steps

- 2 x (3 x - 2) = - 2

Expand

- 2 x (3 x - 2) : - 6 x^{2} + 4 x

- 6 x^{2} + 4 x = - 2

Move

2

to the left side

- 6 x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 6 ) \cdot 2}{2 ( - 6 )}

4^{2} - 4 (- 6) \cdot 2 = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 ( - 6 )}, x_{2} = \frac{- 4 - 8}{2 ( - 6 )}

x = \frac{- 4 + 8}{2 ( - 6 )} : - \frac{1}{3}

x = \frac{- 4 - 8}{2 ( - 6 )} : 1

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = 1

5 x - 2 x^{2} = 0

(x + 4) (2 x - 1) - 1 = - 3 x (x + 2)

(x - 5) (x + 1) = 2 (x - 2)^{2}

x^{2} = (x - 2)^{2} + (x - 9)^{2}

7^{2} + 3^{2} = x^{2}

What are the solutions to the equation -2x(3x-2)=-2 ?
The solutions to the equation -2x(3x-2)=-2 are x=-1/3 ,x=1
Find the zeros of -2x(3x-2)=-2
The zeros of -2x(3x-2)=-2 are x=-1/3 ,x=1