What are the solutions to the equation x^2-12x+48=0 ?

The solutions to the equation x^2-12x+48=0 are x=6+2sqrt(3)i,x=6-2sqrt(3)i

Find the zeros of x^2-12x+48=0

The zeros of x^2-12x+48=0 are x=6+2sqrt(3)i,x=6-2sqrt(3)i

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x^{2} - 12 x + 48 = 0

x = 6 + 23 i, x = 6 - 23 i

Solution steps

x^{2} - 12 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 48 : 43 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 3 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 3 i}{2 \cdot 1} : 6 + 23 i

x = \frac{- ( - 12 ) - 4 3 i}{2 \cdot 1} : 6 - 23 i

The solutions to the quadratic equation are:

x = 6 + 23 i, x = 6 - 23 i

2 x^{2} - x + 1

25 x^{2} + 30 x = 12

5 x^{2} - 360 x = 0

5 x^{2} - 6 = - 6 x

4 a^{2} + 19 = 68

What are the solutions to the equation x^2-12x+48=0 ?
The solutions to the equation x^2-12x+48=0 are x=6+2sqrt(3)i,x=6-2sqrt(3)i
Find the zeros of x^2-12x+48=0
The zeros of x^2-12x+48=0 are x=6+2sqrt(3)i,x=6-2sqrt(3)i