What are the solutions to the equation 2x^2+4x=10 ?

The solutions to the equation 2x^2+4x=10 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of 2x^2+4x=10

The zeros of 2x^2+4x=10 are x=-1+sqrt(6),x=-1-sqrt(6)

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2 x^{2} + 4 x = 10

x = - 1 + 6, x = - 1 - 6

Decimal Notation

x = 1.44948 \dots, x = - 3.44948 \dots

Solution steps

2 x^{2} + 4 x = 10

Move

10

to the left side

2 x^{2} + 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 10) = 46

x_{1, 2} = \frac{- 4 \pm 4 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 4 6}{2 \cdot 2}, x_{2} = \frac{- 4 - 4 6}{2 \cdot 2}

x = \frac{- 4 + 4 6}{2 \cdot 2} : - 1 + 6

x = \frac{- 4 - 4 6}{2 \cdot 2} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

3 x^{2} - 5 x + 2 = 0

2.3 x^{2} - 15 x - 3.1 = 0

3 x^{2} + 7 x - 13 = 0

(x + 2) (x + 2) = (x + 2) 2

4 b^{2} - 4 b - 35 = 0

What are the solutions to the equation 2x^2+4x=10 ?
The solutions to the equation 2x^2+4x=10 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of 2x^2+4x=10
The zeros of 2x^2+4x=10 are x=-1+sqrt(6),x=-1-sqrt(6)