What are the solutions to the equation 1-2x+x^2=2x+1 ?

The solutions to the equation 1-2x+x^2=2x+1 are x=4,x=0

Find the zeros of 1-2x+x^2=2x+1

The zeros of 1-2x+x^2=2x+1 are x=4,x=0

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1 - 2 x + x^{2} = 2 x + 1

x = 4, x = 0

Solution steps

1 - 2 x + x^{2} = 2 x + 1

Move

1

to the left side

x^{2} - 2 x = 2 x

Move

2 x

to the left side

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

x, y = (x - y)^{2}

4 - 25 x^{2} = 0

x^{2} - 2 x + 10

9 m^{2} + 24 m + 16 = 0

x^{2} - \frac{1}{9} = 0

What are the solutions to the equation 1-2x+x^2=2x+1 ?
The solutions to the equation 1-2x+x^2=2x+1 are x=4,x=0
Find the zeros of 1-2x+x^2=2x+1
The zeros of 1-2x+x^2=2x+1 are x=4,x=0