What are the solutions to the equation 7a^2-19a+10=0 ?

The solutions to the equation 7a^2-19a+10=0 are a=2,a= 5/7

Find the zeros of 7a^2-19a+10=0

The zeros of 7a^2-19a+10=0 are a=2,a= 5/7

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7 a^{2} - 19 a + 10 = 0

a = 2, a = \frac{5}{7}

Decimal Notation

a = 2, a = 0.71428 \dots

Solution steps

7 a^{2} - 19 a + 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 7 \cdot 10}{2 \cdot 7}

(- 19)^{2} - 4 \cdot 7 \cdot 10 = 9

a_{1, 2} = \frac{- ( - 19 ) \pm 9}{2 \cdot 7}

Separate the solutions

a_{1} = \frac{- ( - 19 ) + 9}{2 \cdot 7}, a_{2} = \frac{- ( - 19 ) - 9}{2 \cdot 7}

a = \frac{- ( - 19 ) + 9}{2 \cdot 7} : 2

a = \frac{- ( - 19 ) - 9}{2 \cdot 7} : \frac{5}{7}

The solutions to the quadratic equation are:

a = 2, a = \frac{5}{7}

- 2 x^{2} + 8 x - 4

x^{2} - 8 x - 9 = 0

a^{2} + 3^{2} = 4^{2}

(x + 2) (x - 3) = 5

x^{2} = 8 x - 4

What are the solutions to the equation 7a^2-19a+10=0 ?
The solutions to the equation 7a^2-19a+10=0 are a=2,a= 5/7
Find the zeros of 7a^2-19a+10=0
The zeros of 7a^2-19a+10=0 are a=2,a= 5/7