What are the solutions to the equation 7x^2-2x-8=0 ?

The solutions to the equation 7x^2-2x-8=0 are x=(1+sqrt(57))/7 ,x=(1-sqrt(57))/7

Find the zeros of 7x^2-2x-8=0

The zeros of 7x^2-2x-8=0 are x=(1+sqrt(57))/7 ,x=(1-sqrt(57))/7

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7 x^{2} - 2 x - 8 = 0

x = \frac{1 + 57}{7}, x = \frac{1 - 57}{7}

Decimal Notation

x = 1.22140 \dots, x = - 0.93569 \dots

Solution steps

7 x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 8 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 8) = 257

x_{1, 2} = \frac{- ( - 2 ) \pm 2 57}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 57}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 2 57}{2 \cdot 7}

x = \frac{- ( - 2 ) + 2 57}{2 \cdot 7} : \frac{1 + 57}{7}

x = \frac{- ( - 2 ) - 2 57}{2 \cdot 7} : \frac{1 - 57}{7}

The solutions to the quadratic equation are:

x = \frac{1 + 57}{7}, x = \frac{1 - 57}{7}

x^{2} - 2 x - 24 = 0

a, f (a + 1) = (a + 1)^{2} + 3 (a + 1) - 4

x^{2} - 22 x + 57 = 0

4 x^{2} - 40 = 0

4 r^{2} - 1 = 0

What are the solutions to the equation 7x^2-2x-8=0 ?
The solutions to the equation 7x^2-2x-8=0 are x=(1+sqrt(57))/7 ,x=(1-sqrt(57))/7
Find the zeros of 7x^2-2x-8=0
The zeros of 7x^2-2x-8=0 are x=(1+sqrt(57))/7 ,x=(1-sqrt(57))/7