What are the solutions to the equation 1/4 (b-8)^2=7 ?

The solutions to the equation 1/4 (b-8)^2=7 are b=2sqrt(7)+8,b=-2sqrt(7)+8

Find the zeros of 1/4 (b-8)^2=7

The zeros of 1/4 (b-8)^2=7 are b=2sqrt(7)+8,b=-2sqrt(7)+8

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\frac{1}{4} (b - 8)^{2} = 7

b = 27 + 8, b = - 27 + 8

Decimal Notation

b = 13.29150 \dots, b = 2.70849 \dots

Solution steps

\frac{1}{4} (b - 8)^{2} = 7

Multiply both sides by

4

(b - 8)^{2} = 28

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

b - 8 = 28 : b = 27 + 8

Solve

b - 8 = - 28 : b = - 27 + 8

The solutions to the quadratic equation are:

b = 27 + 8, b = - 27 + 8

2 r^{2} - 5 r + 2 = 0

(2 x - 1)^{2} = (x + 2)^{2}

6 x = x^{2} + 8

3 (x - 7)^{2} = 243 + 75 (x + 2)^{2}

n^{2} - 8 n = 0

What are the solutions to the equation 1/4 (b-8)^2=7 ?
The solutions to the equation 1/4 (b-8)^2=7 are b=2sqrt(7)+8,b=-2sqrt(7)+8
Find the zeros of 1/4 (b-8)^2=7
The zeros of 1/4 (b-8)^2=7 are b=2sqrt(7)+8,b=-2sqrt(7)+8