What are the solutions to the equation 3^2+b^2=7^2 ?

The solutions to the equation 3^2+b^2=7^2 are b=2sqrt(10),b=-2sqrt(10)

Find the zeros of 3^2+b^2=7^2

The zeros of 3^2+b^2=7^2 are b=2sqrt(10),b=-2sqrt(10)

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3^{2} + b^{2} = 7^{2}

b = 210, b = - 210

Decimal Notation

b = 6.32455 \dots, b = - 6.32455 \dots

Solution steps

3^{2} + b^{2} = 7^{2}

Move

3^{2}

to the right side

b^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 40, b = - 40

40 = 210

- 40 = - 210

b = 210, b = - 210

2 x^{2} - 5 x + 67 = 0

3 x^{2} + 6 x = 8

x^{2} - \frac{1}{6} x - \frac{1}{6} = 0

k^{2} + 2 k - 3 = 0

x^{2} + 12 x + 20 = 0

What are the solutions to the equation 3^2+b^2=7^2 ?
The solutions to the equation 3^2+b^2=7^2 are b=2sqrt(10),b=-2sqrt(10)
Find the zeros of 3^2+b^2=7^2
The zeros of 3^2+b^2=7^2 are b=2sqrt(10),b=-2sqrt(10)