What are the solutions to the equation 2x^2=7 ?

The solutions to the equation 2x^2=7 are x=sqrt(7/2),x=-sqrt(7/2)

Find the zeros of 2x^2=7

The zeros of 2x^2=7 are x=sqrt(7/2),x=-sqrt(7/2)

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2 x^{2} = 7

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.87082 \dots, x = - 1.87082 \dots

Solution steps

2 x^{2} = 7

Divide both sides by

2

x^{2} = \frac{7}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{2}, x = - \frac{7}{2}

x^{2} + 14 = 10 x

(m + 1) x^{2} - (m + 8) x + 10 = 0

x^{2} - 12 x + 36 = 144

3 x^{2} - 8 x = 0

x^{2} - \frac{10}{4} = \frac{15}{4}

What are the solutions to the equation 2x^2=7 ?
The solutions to the equation 2x^2=7 are x=sqrt(7/2),x=-sqrt(7/2)
Find the zeros of 2x^2=7
The zeros of 2x^2=7 are x=sqrt(7/2),x=-sqrt(7/2)