What are the solutions to the equation 2x^2+14x=120 ?

The solutions to the equation 2x^2+14x=120 are x=5,x=-12

Find the zeros of 2x^2+14x=120

The zeros of 2x^2+14x=120 are x=5,x=-12

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2 x^{2} + 14 x = 120

x = 5, x = - 12

Solution steps

2 x^{2} + 14 x = 120

Move

120

to the left side

2 x^{2} + 14 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 2 ( - 120 )}{2 \cdot 2}

1 4^{2} - 4 \cdot 2 (- 120) = 34

x_{1, 2} = \frac{- 14 \pm 34}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 14 + 34}{2 \cdot 2}, x_{2} = \frac{- 14 - 34}{2 \cdot 2}

x = \frac{- 14 + 34}{2 \cdot 2} : 5

x = \frac{- 14 - 34}{2 \cdot 2} : - 12

The solutions to the quadratic equation are:

x = 5, x = - 12

6 \geq - w + 5

- 3 x < - 12

\frac{1 - \frac{1}{2}}{1 + \frac{1}{2}}

16 x - 38 = 35 - 27 x

What are the solutions to the equation 2x^2+14x=120 ?
The solutions to the equation 2x^2+14x=120 are x=5,x=-12
Find the zeros of 2x^2+14x=120
The zeros of 2x^2+14x=120 are x=5,x=-12