What are the solutions to the equation -x^2+8x+1=0 ?

The solutions to the equation -x^2+8x+1=0 are x=4-sqrt(17),x=4+sqrt(17)

Find the zeros of -x^2+8x+1=0

The zeros of -x^2+8x+1=0 are x=4-sqrt(17),x=4+sqrt(17)

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- x^{2} + 8 x + 1 = 0

x = 4 - 17, x = 4 + 17

Decimal Notation

x = - 0.12310 \dots, x = 8.12310 \dots

Solution steps

- x^{2} + 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 1 = 217

x_{1, 2} = \frac{- 8 \pm 2 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 17}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 17}{2 ( - 1 )}

x = \frac{- 8 + 2 17}{2 ( - 1 )} : 4 - 17

x = \frac{- 8 - 2 17}{2 ( - 1 )} : 4 + 17

The solutions to the quadratic equation are:

x = 4 - 17, x = 4 + 17

x^{2} - x = 7

x^{2} + 12 x - 18 = 0

90 x^{2} + 11 x - 2 = 0

x^{2} + 2 x - 31 = 0

7 x^{2} - 8 x = 0

What are the solutions to the equation -x^2+8x+1=0 ?
The solutions to the equation -x^2+8x+1=0 are x=4-sqrt(17),x=4+sqrt(17)
Find the zeros of -x^2+8x+1=0
The zeros of -x^2+8x+1=0 are x=4-sqrt(17),x=4+sqrt(17)