What are the solutions to the equation x^2+9x+16=2x+6 ?

The solutions to the equation x^2+9x+16=2x+6 are x=-2,x=-5

Find the zeros of x^2+9x+16=2x+6

The zeros of x^2+9x+16=2x+6 are x=-2,x=-5

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x^{2} + 9 x + 16 = 2 x + 6

x = - 2, x = - 5

Solution steps

x^{2} + 9 x + 16 = 2 x + 6

Move

6

to the left side

x^{2} + 9 x + 10 = 2 x

Move

2 x

to the left side

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

5 x^{2} - 7 x + 4 = 0

9 x^{2} = 63 x

x^{2} - 2 x = 120

x^{2} - 29 x + 120 = 0

2 x^{2} + 8 x - 2 = 0

What are the solutions to the equation x^2+9x+16=2x+6 ?
The solutions to the equation x^2+9x+16=2x+6 are x=-2,x=-5
Find the zeros of x^2+9x+16=2x+6
The zeros of x^2+9x+16=2x+6 are x=-2,x=-5