What are the solutions to the equation 6x^2+2x-8=0 ?

The solutions to the equation 6x^2+2x-8=0 are x=1,x=-4/3

Find the zeros of 6x^2+2x-8=0

The zeros of 6x^2+2x-8=0 are x=1,x=-4/3

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6 x^{2} + 2 x - 8 = 0

x = 1, x = - \frac{4}{3}

Decimal Notation

x = 1, x = - 1.33333 \dots

Solution steps

6 x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 8 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 8) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 6}, x_{2} = \frac{- 2 - 14}{2 \cdot 6}

x = \frac{- 2 + 14}{2 \cdot 6} : 1

x = \frac{- 2 - 14}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{3}

x^{2} - 81 = 0

4 (x^{2} + 1) = 3 (x^{2} + 3) + 4

4 x^{2} - 16 x

0 = 3 x^{2} - 8 x - 16

7 x (x - 2) = 3 - 2 (x + 4)

What are the solutions to the equation 6x^2+2x-8=0 ?
The solutions to the equation 6x^2+2x-8=0 are x=1,x=-4/3
Find the zeros of 6x^2+2x-8=0
The zeros of 6x^2+2x-8=0 are x=1,x=-4/3