What are the solutions to the equation x^2-x+6=3 ?

The solutions to the equation x^2-x+6=3 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

Find the zeros of x^2-x+6=3

The zeros of x^2-x+6=3 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

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x^{2} - x + 6 = 3

x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

Solution steps

x^{2} - x + 6 = 3

Move

3

to the left side

x^{2} - x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 3 : 11 i

x_{1, 2} = \frac{- ( - 1 ) \pm 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 11 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 11 i}{2 \cdot 1} : \frac{1}{2} + i \frac{11}{2}

x = \frac{- ( - 1 ) - 11 i}{2 \cdot 1} : \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

12 x^{2} - 120 x + 216 = 0

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x^{2} - 1.6 x + 0.63 = 0

\frac{4 ( t - 1.4 ) ^{2}}{2} = \frac{87 t}{3.6}

2 x^{2} + 5 x + 2

What are the solutions to the equation x^2-x+6=3 ?
The solutions to the equation x^2-x+6=3 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2
Find the zeros of x^2-x+6=3
The zeros of x^2-x+6=3 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2