What are the solutions to the equation 4/3 x^2= 2/3 x^2+6 ?

The solutions to the equation 4/3 x^2= 2/3 x^2+6 are x=3,x=-3

Find the zeros of 4/3 x^2= 2/3 x^2+6

The zeros of 4/3 x^2= 2/3 x^2+6 are x=3,x=-3

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\frac{4}{3} x^{2} = \frac{2}{3} x^{2} + 6

x = 3, x = - 3

Solution steps

\frac{4}{3} x^{2} = \frac{2}{3} x^{2} + 6

Move

\frac{2}{3} x^{2}

to the left side

\frac{2}{3} x^{2} = 6

Multiply both sides by

3

2 x^{2} = 18

Divide both sides by

2

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

x^{2} - 2 x - 4

x^{2} - 2 x - 2

x^{2} - 2 x + 3

u^{2} - 4 = 0

4 t^{2} + t + 1 = 0

What are the solutions to the equation 4/3 x^2= 2/3 x^2+6 ?
The solutions to the equation 4/3 x^2= 2/3 x^2+6 are x=3,x=-3
Find the zeros of 4/3 x^2= 2/3 x^2+6
The zeros of 4/3 x^2= 2/3 x^2+6 are x=3,x=-3