What are the solutions to the equation 10b^2-10=-141 ?

The solutions to the equation 10b^2-10=-141 are b=sqrt(131/10)i,b=-sqrt(131/10)i

Find the zeros of 10b^2-10=-141

The zeros of 10b^2-10=-141 are b=sqrt(131/10)i,b=-sqrt(131/10)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 b^{2} - 10 = - 141

b = \frac{131}{10} i, b = - \frac{131}{10} i

Solution steps

10 b^{2} - 10 = - 141

Move

10

to the right side

10 b^{2} = - 131

Divide both sides by

10

b^{2} = - \frac{131}{10}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = - \frac{131}{10}, b = - - \frac{131}{10}

- \frac{131}{10} = \frac{131}{10} i

- - \frac{131}{10} = - \frac{131}{10} i

b = \frac{131}{10} i, b = - \frac{131}{10} i

x (x - 56) = 0

x, y^{2} = 4 x^{2}

5 x - 24 = - x^{2}

y = 0.00249 (1 - \frac{0.5714 - 2000 y}{- 2})^{2}

- 5 x^{2} + 7 x - 2 = 0

What are the solutions to the equation 10b^2-10=-141 ?
The solutions to the equation 10b^2-10=-141 are b=sqrt(131/10)i,b=-sqrt(131/10)i
Find the zeros of 10b^2-10=-141
The zeros of 10b^2-10=-141 are b=sqrt(131/10)i,b=-sqrt(131/10)i