What are the solutions to the equation -x^2+12=0 ?

The solutions to the equation -x^2+12=0 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of -x^2+12=0

The zeros of -x^2+12=0 are x=2sqrt(3),x=-2sqrt(3)

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Popular >

- x^{2} + 12 = 0

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

- x^{2} + 12 = 0

Move

12

to the right side

- x^{2} = - 12

Divide both sides by

- 1

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

6 x^{2} - 3 x - 9 = 0

x^{2} - x - 20 = 0

(x - 2) (x - 2) = 0

(x + 4)^{2} + 15 = 0

7 x^{2} - 9 x - 9 = 0

What are the solutions to the equation -x^2+12=0 ?
The solutions to the equation -x^2+12=0 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of -x^2+12=0
The zeros of -x^2+12=0 are x=2sqrt(3),x=-2sqrt(3)