What are the solutions to the equation 7x^2+5x-1=0 ?

The solutions to the equation 7x^2+5x-1=0 are x=(-5+sqrt(53))/(14),x=(-5-sqrt(53))/(14)

Find the zeros of 7x^2+5x-1=0

The zeros of 7x^2+5x-1=0 are x=(-5+sqrt(53))/(14),x=(-5-sqrt(53))/(14)

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7 x^{2} + 5 x - 1 = 0

x = \frac{- 5 + 53}{14}, x = \frac{- 5 - 53}{14}

Decimal

x = 0.16286 \dots, x = - 0.87715 \dots

Solution steps

7 x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

5^{2} - 4 \cdot 7 (- 1) = 53

x_{1, 2} = \frac{- 5 \pm 53}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 5 + 53}{2 \cdot 7}, x_{2} = \frac{- 5 - 53}{2 \cdot 7}

x = \frac{- 5 + 53}{2 \cdot 7} : \frac{- 5 + 53}{14}

x = \frac{- 5 - 53}{2 \cdot 7} : \frac{- 5 - 53}{14}

The solutions to the quadratic equation are:

x = \frac{- 5 + 53}{14}, x = \frac{- 5 - 53}{14}

x^{2} - x + c = 0

3 x^{2} - 24 x + 27 = 0

3 = (1 - 2 (1) + 5) t^{2} + (2 (1) - 2 (1)) t + 1

x^{2} + 4^{2} = 7^{2}

2 y^{2} + 16 y = - 8

What are the solutions to the equation 7x^2+5x-1=0 ?
The solutions to the equation 7x^2+5x-1=0 are x=(-5+sqrt(53))/(14),x=(-5-sqrt(53))/(14)
Find the zeros of 7x^2+5x-1=0
The zeros of 7x^2+5x-1=0 are x=(-5+sqrt(53))/(14),x=(-5-sqrt(53))/(14)