What are the solutions to the equation 12x^2-12x-72=0 ?

The solutions to the equation 12x^2-12x-72=0 are x=3,x=-2

Find the zeros of 12x^2-12x-72=0

The zeros of 12x^2-12x-72=0 are x=3,x=-2

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12 x^{2} - 12 x - 72 = 0

x = 3, x = - 2

Solution steps

12 x^{2} - 12 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 12 ( - 72 )}{2 \cdot 12}

(- 12)^{2} - 4 \cdot 12 (- 72) = 60

x_{1, 2} = \frac{- ( - 12 ) \pm 60}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 60}{2 \cdot 12}, x_{2} = \frac{- ( - 12 ) - 60}{2 \cdot 12}

x = \frac{- ( - 12 ) + 60}{2 \cdot 12} : 3

x = \frac{- ( - 12 ) - 60}{2 \cdot 12} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

9 x^{2} - 8 x + 1 = 0

2 x^{2} + 5 x - 1 = 0

y, f = x^{4} y^{2} - x^{3} y

4 x^{2} - 12 = 2 x

6 x^{2} - 486 = 0

What are the solutions to the equation 12x^2-12x-72=0 ?
The solutions to the equation 12x^2-12x-72=0 are x=3,x=-2
Find the zeros of 12x^2-12x-72=0
The zeros of 12x^2-12x-72=0 are x=3,x=-2