What are the solutions to the equation 120-x^2=32+3x ?

The solutions to the equation 120-x^2=32+3x are x=-11,x=8

Find the zeros of 120-x^2=32+3x

The zeros of 120-x^2=32+3x are x=-11,x=8

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120 - x^{2} = 32 + 3 x

x = - 11, x = 8

Solution steps

120 - x^{2} = 32 + 3 x

Move

3 x

to the left side

120 - x^{2} - 3 x = 32

Move

32

to the left side

- x^{2} - 3 x + 88 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 88}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 88 = 19

x_{1, 2} = \frac{- ( - 3 ) \pm 19}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 19}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 19}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 19}{2 ( - 1 )} : - 11

x = \frac{- ( - 3 ) - 19}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = - 11, x = 8

- 2 x^{2} - 16 x - 24 = 0

- x^{2} + x + 5 = 0

x^{2} + 8 x + 6 = 0

(3 x + 2)^{2} = 18

(2 x + 3) (x + 4) = 7

What are the solutions to the equation 120-x^2=32+3x ?
The solutions to the equation 120-x^2=32+3x are x=-11,x=8
Find the zeros of 120-x^2=32+3x
The zeros of 120-x^2=32+3x are x=-11,x=8