What are the solutions to the equation -5x^2+210x+1=2161 ?

The solutions to the equation -5x^2+210x+1=2161 are x=18,x=24

Find the zeros of -5x^2+210x+1=2161

The zeros of -5x^2+210x+1=2161 are x=18,x=24

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- 5 x^{2} + 210 x + 1 = 2161

x = 18, x = 24

Solution steps

- 5 x^{2} + 210 x + 1 = 2161

Move

2161

to the left side

- 5 x^{2} + 210 x - 2160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 210 \pm 21 0 ^{2} - 4 ( - 5 ) ( - 2160 )}{2 ( - 5 )}

21 0^{2} - 4 (- 5) (- 2160) = 30

x_{1, 2} = \frac{- 210 \pm 30}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 210 + 30}{2 ( - 5 )}, x_{2} = \frac{- 210 - 30}{2 ( - 5 )}

x = \frac{- 210 + 30}{2 ( - 5 )} : 18

x = \frac{- 210 - 30}{2 ( - 5 )} : 24

The solutions to the quadratic equation are:

x = 18, x = 24

- 4 x^{2} - 2 x + 1 = 0

x, f = x^{2} + k

x, f = x^{2} + y

4 x^{2} - 16 x = 48

4 x^{2} + 107 x + 313 = - x^{2} + 7 x - 7

What are the solutions to the equation -5x^2+210x+1=2161 ?
The solutions to the equation -5x^2+210x+1=2161 are x=18,x=24
Find the zeros of -5x^2+210x+1=2161
The zeros of -5x^2+210x+1=2161 are x=18,x=24