What are the solutions to the equation 0=-16(t)^2+50(t)+10 ?

The solutions to the equation 0=-16(t)^2+50(t)+10 are t=-(-25+sqrt(785))/(16),t=(25+sqrt(785))/(16)

Find the zeros of 0=-16(t)^2+50(t)+10

The zeros of 0=-16(t)^2+50(t)+10 are t=-(-25+sqrt(785))/(16),t=(25+sqrt(785))/(16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 (t)^{2} + 50 (t) + 10

t = - \frac{- 25 + 785}{16}, t = \frac{25 + 785}{16}

Decimal Notation

t = - 0.18861 \dots, t = 3.31361 \dots

Solution steps

0 = - 16 t^{2} + 50 (t) + 10

Refine

0 = - 16 t^{2} + 50 t + 10

Switch sides

- 16 t^{2} + 50 t + 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 16 ) \cdot 10}{2 ( - 16 )}

5 0^{2} - 4 (- 16) \cdot 10 = 2785

t_{1, 2} = \frac{- 50 \pm 2 785}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 50 + 2 785}{2 ( - 16 )}, t_{2} = \frac{- 50 - 2 785}{2 ( - 16 )}

t = \frac{- 50 + 2 785}{2 ( - 16 )} : - \frac{- 25 + 785}{16}

t = \frac{- 50 - 2 785}{2 ( - 16 )} : \frac{25 + 785}{16}

The solutions to the quadratic equation are:

t = - \frac{- 25 + 785}{16}, t = \frac{25 + 785}{16}

9 x^{2} + 7 x - 2 = 0

- 3 x^{2} - 9 x - 1 = 0

w^{2} - 2 w = 0

49 m^{2} = 49 m - 12

8 x^{2} = 16

What are the solutions to the equation 0=-16(t)^2+50(t)+10 ?
The solutions to the equation 0=-16(t)^2+50(t)+10 are t=-(-25+sqrt(785))/(16),t=(25+sqrt(785))/(16)
Find the zeros of 0=-16(t)^2+50(t)+10
The zeros of 0=-16(t)^2+50(t)+10 are t=-(-25+sqrt(785))/(16),t=(25+sqrt(785))/(16)