What are the solutions to the equation 3w^2+27w=0 ?

The solutions to the equation 3w^2+27w=0 are w=0,w=-9

Find the zeros of 3w^2+27w=0

The zeros of 3w^2+27w=0 are w=0,w=-9

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3 w^{2} + 27 w = 0

w = 0, w = - 9

Solution steps

3 w^{2} + 27 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

2 7^{2} - 4 \cdot 3 \cdot 0 = 27

w_{1, 2} = \frac{- 27 \pm 27}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 27 + 27}{2 \cdot 3}, w_{2} = \frac{- 27 - 27}{2 \cdot 3}

w = \frac{- 27 + 27}{2 \cdot 3} : 0

w = \frac{- 27 - 27}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

w = 0, w = - 9

a, b a^{2} + 3 = N^{3}

5 y^{2} - y^{2} = 10

λ^{2} - 3 λ + 2 = 0

4 x^{2} = x + 5

a, a^{2} x^{2} + b^{2} y^{2} = a^{2} b^{2}

What are the solutions to the equation 3w^2+27w=0 ?
The solutions to the equation 3w^2+27w=0 are w=0,w=-9
Find the zeros of 3w^2+27w=0
The zeros of 3w^2+27w=0 are w=0,w=-9