What are the solutions to the equation 1/4 x^2+2x+4=0 ?

The solutions to the equation 1/4 x^2+2x+4=0 are x=-4

Find the zeros of 1/4 x^2+2x+4=0

The zeros of 1/4 x^2+2x+4=0 are x=-4

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\frac{1}{4} x^{2} + 2 x + 4 = 0

x = - 4

Solution steps

\frac{1}{4} x^{2} + 2 x + 4 = 0

Multiply both sides by

4

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

x (x + 5) = 84

x, \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{25} = 1

(x + 1)^{2} = 24

4 x^{2} + 12 x - 9 = 0

5 x^{2} + 4 = 0

What are the solutions to the equation 1/4 x^2+2x+4=0 ?
The solutions to the equation 1/4 x^2+2x+4=0 are x=-4
Find the zeros of 1/4 x^2+2x+4=0
The zeros of 1/4 x^2+2x+4=0 are x=-4