What is ((2xy^3)/(3x^2z))^3 ?

The solution to ((2xy^3)/(3x^2z))^3 is (8y^9)/(27x^3z^3)

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simplify ((2xy^3)/(3x^2z))^3

simplify

(\frac{2 x y ^{3}}{3 x ^{2} z})^{3}

\frac{8 y ^{9}}{27 x ^{3} z ^{3}}

Solution steps

(\frac{2 x y ^{3}}{3 x ^{2} z})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x y ^{3} ) ^{3}}{( 3 x ^{2} z ) ^{3}}

Simplify

(2 x y^{3})^{3} : 8 x^{3} y^{9}

= \frac{8 x ^{3} y ^{9}}{( 3 x ^{2} z ) ^{3}}

Simplify

(3 x^{2} z)^{3} : 27 x^{6} z^{3}

= \frac{8 x ^{3} y ^{9}}{27 x ^{6} z ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{3}}{x ^{6}} = \frac{1}{x ^{6 - 3}}

= \frac{8 y ^{9}}{27 z ^{3} x ^{6 - 3}}

Subtract the numbers:

6 - 3 = 3

= \frac{8 y ^{9}}{27 x ^{3} z ^{3}}

12 x^{2} - 84 x + 104 = 0

6 - x - x^{2}

2 x + 5 + 2 x + 3 x = 2 x + 5

∣ 5 x + 7 ∣ + 6 < 3

y^{4} + 12 y^{3} + 35 y^{2}

What is ((2xy^3)/(3x^2z))^3 ?
The solution to ((2xy^3)/(3x^2z))^3 is (8y^9)/(27x^3z^3)