What are the solutions to the equation 6a^2-4a-22=0 ?

The solutions to the equation 6a^2-4a-22=0 are a=(1+sqrt(34))/3 ,a=(1-sqrt(34))/3

Find the zeros of 6a^2-4a-22=0

The zeros of 6a^2-4a-22=0 are a=(1+sqrt(34))/3 ,a=(1-sqrt(34))/3

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6 a^{2} - 4 a - 22 = 0

a = \frac{1 + 34}{3}, a = \frac{1 - 34}{3}

Decimal Notation

a = 2.27698 \dots, a = - 1.61031 \dots

Solution steps

6 a^{2} - 4 a - 22 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 ( - 22 )}{2 \cdot 6}

(- 4)^{2} - 4 \cdot 6 (- 22) = 434

a_{1, 2} = \frac{- ( - 4 ) \pm 4 34}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- ( - 4 ) + 4 34}{2 \cdot 6}, a_{2} = \frac{- ( - 4 ) - 4 34}{2 \cdot 6}

a = \frac{- ( - 4 ) + 4 34}{2 \cdot 6} : \frac{1 + 34}{3}

a = \frac{- ( - 4 ) - 4 34}{2 \cdot 6} : \frac{1 - 34}{3}

The solutions to the quadratic equation are:

a = \frac{1 + 34}{3}, a = \frac{1 - 34}{3}

x, 3 x^{2} + 2 x y + y^{2} = 1

- 3 x^{2} + 2 x + 3 = 0

- x^{2} + 12 x - 32 = 0

x^{2} = 9^{2} + 1 2^{2}

2 x^{2} + 8 x - 1

What are the solutions to the equation 6a^2-4a-22=0 ?
The solutions to the equation 6a^2-4a-22=0 are a=(1+sqrt(34))/3 ,a=(1-sqrt(34))/3
Find the zeros of 6a^2-4a-22=0
The zeros of 6a^2-4a-22=0 are a=(1+sqrt(34))/3 ,a=(1-sqrt(34))/3