What are the solutions to the equation x^2-22x+c=75+c ?

The solutions to the equation x^2-22x+c=75+c are x=25,x=-3

Find the zeros of x^2-22x+c=75+c

The zeros of x^2-22x+c=75+c are x=25,x=-3

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x^{2} - 22 x + c = 75 + c

x = 25, x = - 3

Solution steps

x^{2} - 22 x + c = 75 + c

Move

c

to the left side

x^{2} - 22 x = 75

Move

75

to the left side

x^{2} - 22 x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 1 \cdot ( - 75 )}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot (- 75) = 28

x_{1, 2} = \frac{- ( - 22 ) \pm 28}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 28}{2 \cdot 1}, x_{2} = \frac{- ( - 22 ) - 28}{2 \cdot 1}

x = \frac{- ( - 22 ) + 28}{2 \cdot 1} : 25

x = \frac{- ( - 22 ) - 28}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 25, x = - 3

5 (2 x - 4) = (x + 2) (3 - x) - 4

x^{2} + 5 x = 150

2 m^{2} - 2 m - 4 = 0

9 x^{2} - 5 x + 1 = 0

- 8 x^{2} - 3 x - 8 = 0

What are the solutions to the equation x^2-22x+c=75+c ?
The solutions to the equation x^2-22x+c=75+c are x=25,x=-3
Find the zeros of x^2-22x+c=75+c
The zeros of x^2-22x+c=75+c are x=25,x=-3