What are the solutions to the equation 12^2+13^2=c^2 ?

The solutions to the equation 12^2+13^2=c^2 are c=sqrt(313),c=-sqrt(313)

Find the zeros of 12^2+13^2=c^2

The zeros of 12^2+13^2=c^2 are c=sqrt(313),c=-sqrt(313)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 2^{2} + 1 3^{2} = c^{2}

c = 313, c = - 313

Decimal Notation

c = 17.69180 \dots, c = - 17.69180 \dots

Solution steps

1 2^{2} + 1 3^{2} = c^{2}

Switch sides

c^{2} = 1 2^{2} + 1 3^{2}

Simplify

1 2^{2} + 1 3^{2} : 313

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 313, c = - 313

6 x^{2} - 54 = 5 x^{2} + 171

x^{2} - 6 x + 9

x^{2} + x - 6 = 24

x^{2} + 9 + 20 = 0

(x - 6) (x - 3) = 0

What are the solutions to the equation 12^2+13^2=c^2 ?
The solutions to the equation 12^2+13^2=c^2 are c=sqrt(313),c=-sqrt(313)
Find the zeros of 12^2+13^2=c^2
The zeros of 12^2+13^2=c^2 are c=sqrt(313),c=-sqrt(313)