What are the solutions to the equation 36x^2-24x+4=81 ?

The solutions to the equation 36x^2-24x+4=81 are x= 11/6 ,x=-7/6

Find the zeros of 36x^2-24x+4=81

The zeros of 36x^2-24x+4=81 are x= 11/6 ,x=-7/6

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36 x^{2} - 24 x + 4 = 81

x = \frac{11}{6}, x = - \frac{7}{6}

Decimal Notation

x = 1.83333 \dots, x = - 1.16666 \dots

Solution steps

36 x^{2} - 24 x + 4 = 81

Move

81

to the left side

36 x^{2} - 24 x - 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 36 ( - 77 )}{2 \cdot 36}

(- 24)^{2} - 4 \cdot 36 (- 77) = 108

x_{1, 2} = \frac{- ( - 24 ) \pm 108}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 108}{2 \cdot 36}, x_{2} = \frac{- ( - 24 ) - 108}{2 \cdot 36}

x = \frac{- ( - 24 ) + 108}{2 \cdot 36} : \frac{11}{6}

x = \frac{- ( - 24 ) - 108}{2 \cdot 36} : - \frac{7}{6}

The solutions to the quadratic equation are:

x = \frac{11}{6}, x = - \frac{7}{6}

3 - x^{2} = 3 - 3 x

m^{2} - 10 m + 16 = 0

c^{2} = 9

- 3 x^{2} + 5 = 0

x^{2} - 4 - 12 = 0

What are the solutions to the equation 36x^2-24x+4=81 ?
The solutions to the equation 36x^2-24x+4=81 are x= 11/6 ,x=-7/6
Find the zeros of 36x^2-24x+4=81
The zeros of 36x^2-24x+4=81 are x= 11/6 ,x=-7/6