What are the solutions to the equation 3x^2+12x+6=6 ?

The solutions to the equation 3x^2+12x+6=6 are x=0,x=-4

Find the zeros of 3x^2+12x+6=6

The zeros of 3x^2+12x+6=6 are x=0,x=-4

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3 x^{2} + 12 x + 6 = 6

x = 0, x = - 4

Solution steps

3 x^{2} + 12 x + 6 = 6

Move

6

to the left side

3 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 \cdot 3}, x_{2} = \frac{- 12 - 12}{2 \cdot 3}

x = \frac{- 12 + 12}{2 \cdot 3} : 0

x = \frac{- 12 - 12}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

(x + 2)^{2} = 4 x + 20

12 x^{2} - 44 x + 24 = 0

3 x^{2} + 12 x + 2 = 0

x^{2} + 12 x + 17 = 0

- 3 x^{2} + 2 x - 1 = 0

What are the solutions to the equation 3x^2+12x+6=6 ?
The solutions to the equation 3x^2+12x+6=6 are x=0,x=-4
Find the zeros of 3x^2+12x+6=6
The zeros of 3x^2+12x+6=6 are x=0,x=-4