What are the solutions to the equation -180t^2+30t+14=0 ?

The solutions to the equation -180t^2+30t+14=0 are t=-(-5+sqrt(305))/(60),t=(5+sqrt(305))/(60)

Find the zeros of -180t^2+30t+14=0

The zeros of -180t^2+30t+14=0 are t=-(-5+sqrt(305))/(60),t=(5+sqrt(305))/(60)

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- 180 t^{2} + 30 t + 14 = 0

t = - \frac{- 5 + 305}{60}, t = \frac{5 + 305}{60}

Decimal Notation

t = - 0.20773 \dots, t = 0.37440 \dots

Solution steps

- 180 t^{2} + 30 t + 14 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 ( - 180 ) \cdot 14}{2 ( - 180 )}

3 0^{2} - 4 (- 180) \cdot 14 = 6305

t_{1, 2} = \frac{- 30 \pm 6 305}{2 ( - 180 )}

Separate the solutions

t_{1} = \frac{- 30 + 6 305}{2 ( - 180 )}, t_{2} = \frac{- 30 - 6 305}{2 ( - 180 )}

t = \frac{- 30 + 6 305}{2 ( - 180 )} : - \frac{- 5 + 305}{60}

t = \frac{- 30 - 6 305}{2 ( - 180 )} : \frac{5 + 305}{60}

The solutions to the quadratic equation are:

t = - \frac{- 5 + 305}{60}, t = \frac{5 + 305}{60}

8 x^{2} - 19 x = 2 x^{2} - x

9 x^{2} - 36 x + 36 = 0

r^{2} = 2 r

x^{2} - 6 x = - 14

x^{2} - 6 x = - 22

What are the solutions to the equation -180t^2+30t+14=0 ?
The solutions to the equation -180t^2+30t+14=0 are t=-(-5+sqrt(305))/(60),t=(5+sqrt(305))/(60)
Find the zeros of -180t^2+30t+14=0
The zeros of -180t^2+30t+14=0 are t=-(-5+sqrt(305))/(60),t=(5+sqrt(305))/(60)