What are the solutions to the equation 9m^2+54=5 ?

The solutions to the equation 9m^2+54=5 are m= 7/3 i,m=-7/3 i

Find the zeros of 9m^2+54=5

The zeros of 9m^2+54=5 are m= 7/3 i,m=-7/3 i

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9 m^{2} + 54 = 5

m = \frac{7}{3} i, m = - \frac{7}{3} i

Solution steps

9 m^{2} + 54 = 5

Move

54

to the right side

9 m^{2} = - 49

Divide both sides by

9

m^{2} = - \frac{49}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - \frac{49}{9}, m = - - \frac{49}{9}

- \frac{49}{9} = \frac{7}{3} i

- - \frac{49}{9} = - \frac{7}{3} i

m = \frac{7}{3} i, m = - \frac{7}{3} i

(x + 14) (x - 3) = 0

x^{2} - 8 x + 14

2 x^{2} - 7 x - 21 = 0

y^{2} = 11 y - 28

(2 x + 1) (x - 1) = 0

What are the solutions to the equation 9m^2+54=5 ?
The solutions to the equation 9m^2+54=5 are m= 7/3 i,m=-7/3 i
Find the zeros of 9m^2+54=5
The zeros of 9m^2+54=5 are m= 7/3 i,m=-7/3 i