What are the solutions to the equation 125-x^2=x^2+15x ?

The solutions to the equation 125-x^2=x^2+15x are x=-25/2 ,x=5

Find the zeros of 125-x^2=x^2+15x

The zeros of 125-x^2=x^2+15x are x=-25/2 ,x=5

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125 - x^{2} = x^{2} + 15 x

x = - \frac{25}{2}, x = 5

Decimal Notation

x = - 12.5, x = 5

Solution steps

125 - x^{2} = x^{2} + 15 x

Move

15 x

to the left side

125 - x^{2} - 15 x = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} - 15 x + 125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 ( - 2 ) \cdot 125}{2 ( - 2 )}

(- 15)^{2} - 4 (- 2) \cdot 125 = 35

x_{1, 2} = \frac{- ( - 15 ) \pm 35}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 35}{2 ( - 2 )}, x_{2} = \frac{- ( - 15 ) - 35}{2 ( - 2 )}

x = \frac{- ( - 15 ) + 35}{2 ( - 2 )} : - \frac{25}{2}

x = \frac{- ( - 15 ) - 35}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = - \frac{25}{2}, x = 5

x^{2} \cdot 3 = 33

x^{2} - 4 x + 10 = 0

r^{2} + 32 = 12 r

5200 + 25 x + \frac{1}{2} x^{2} = (195 - \frac{1}{2} x) x

5 x^{2} - 3 x = 8

What are the solutions to the equation 125-x^2=x^2+15x ?
The solutions to the equation 125-x^2=x^2+15x are x=-25/2 ,x=5
Find the zeros of 125-x^2=x^2+15x
The zeros of 125-x^2=x^2+15x are x=-25/2 ,x=5