What are the solutions to the equation x^2-14x+229=0 ?

The solutions to the equation x^2-14x+229=0 are x=7+6sqrt(5)i,x=7-6sqrt(5)i

Find the zeros of x^2-14x+229=0

The zeros of x^2-14x+229=0 are x=7+6sqrt(5)i,x=7-6sqrt(5)i

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x^{2} - 14 x + 229 = 0

x = 7 + 65 i, x = 7 - 65 i

Solution steps

x^{2} - 14 x + 229 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 229}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 229 : 125 i

x_{1, 2} = \frac{- ( - 14 ) \pm 12 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 12 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 12 5 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 12 5 i}{2 \cdot 1} : 7 + 65 i

x = \frac{- ( - 14 ) - 12 5 i}{2 \cdot 1} : 7 - 65 i

The solutions to the quadratic equation are:

x = 7 + 65 i, x = 7 - 65 i

t, p = 3 t^{2} + 10 t - 900

15 x^{2} - 12 = - 8 x

- 0.2 x^{2} + 220 = 0.1 x^{2} + 8 x + 110

x + 1 = 9 - x^{2}

(8 n - 5) (n - 6) = 0

What are the solutions to the equation x^2-14x+229=0 ?
The solutions to the equation x^2-14x+229=0 are x=7+6sqrt(5)i,x=7-6sqrt(5)i
Find the zeros of x^2-14x+229=0
The zeros of x^2-14x+229=0 are x=7+6sqrt(5)i,x=7-6sqrt(5)i