What are the solutions to the equation x^2+6x+4=-2x+4-2x+4 ?

The solutions to the equation x^2+6x+4=-2x+4-2x+4 are x=-5+sqrt(29),x=-5-sqrt(29)

Find the zeros of x^2+6x+4=-2x+4-2x+4

The zeros of x^2+6x+4=-2x+4-2x+4 are x=-5+sqrt(29),x=-5-sqrt(29)

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x^{2} + 6 x + 4 = - 2 x + 4 - 2 x + 4

x = - 5 + 29, x = - 5 - 29

Decimal Notation

x = 0.38516 \dots, x = - 10.38516 \dots

Solution steps

x^{2} + 6 x + 4 = - 2 x + 4 - 2 x + 4

Refine

x^{2} + 6 x + 4 = - 4 x + 8

Move

8

to the left side

x^{2} + 6 x - 4 = - 4 x

Move

4 x

to the left side

x^{2} + 10 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 4) = 229

x_{1, 2} = \frac{- 10 \pm 2 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 29}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 29}{2 \cdot 1}

x = \frac{- 10 + 2 29}{2 \cdot 1} : - 5 + 29

x = \frac{- 10 - 2 29}{2 \cdot 1} : - 5 - 29

The solutions to the quadratic equation are:

x = - 5 + 29, x = - 5 - 29

6 v^{2} - 4 = 0

- x^{2} + 2 x + 5 = 1.5 x

x^{2} - 8 x + 8

2 x^{2} + 4 x

x^{2} + x - 30

What are the solutions to the equation x^2+6x+4=-2x+4-2x+4 ?
The solutions to the equation x^2+6x+4=-2x+4-2x+4 are x=-5+sqrt(29),x=-5-sqrt(29)
Find the zeros of x^2+6x+4=-2x+4-2x+4
The zeros of x^2+6x+4=-2x+4-2x+4 are x=-5+sqrt(29),x=-5-sqrt(29)