What are the solutions to the equation 3+8x+2x^2+8x-42=8x+3 ?

The solutions to the equation 3+8x+2x^2+8x-42=8x+3 are x=3,x=-7

Find the zeros of 3+8x+2x^2+8x-42=8x+3

The zeros of 3+8x+2x^2+8x-42=8x+3 are x=3,x=-7

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3 + 8 x + 2 x^{2} + 8 x - 42 = 8 x + 3

x = 3, x = - 7

Solution steps

3 + 8 x + 2 x^{2} + 8 x - 42 = 8 x + 3

Refine

2 x^{2} + 16 x - 39 = 8 x + 3

Move

3

to the left side

2 x^{2} + 16 x - 42 = 8 x

Move

8 x

to the left side

2 x^{2} + 8 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 42 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 42) = 20

x_{1, 2} = \frac{- 8 \pm 20}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 20}{2 \cdot 2}, x_{2} = \frac{- 8 - 20}{2 \cdot 2}

x = \frac{- 8 + 20}{2 \cdot 2} : 3

x = \frac{- 8 - 20}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

(x + 5)^{2} = 10 x

12 x^{2} + 15 x = 18

49 x^{2} = 56 x - 17

6 x^{2} = 216

6 x^{2} = 21 x

What are the solutions to the equation 3+8x+2x^2+8x-42=8x+3 ?
The solutions to the equation 3+8x+2x^2+8x-42=8x+3 are x=3,x=-7
Find the zeros of 3+8x+2x^2+8x-42=8x+3
The zeros of 3+8x+2x^2+8x-42=8x+3 are x=3,x=-7