What are the solutions to the equation x^2-7.2x+12.8=0 ?

The solutions to the equation x^2-7.2x+12.8=0 are x=4,x= 16/5

Find the zeros of x^2-7.2x+12.8=0

The zeros of x^2-7.2x+12.8=0 are x=4,x= 16/5

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x^{2} - 7.2 x + 12.8 = 0

x = 4, x = \frac{16}{5}

Decimal Notation

x = 4, x = 3.2

Solution steps

x^{2} - 7.2 x + 12.8 = 0

Multiply both sides by

10

10 x^{2} - 72 x + 128 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 10 \cdot 128}{2 \cdot 10}

(- 72)^{2} - 4 \cdot 10 \cdot 128 = 8

x_{1, 2} = \frac{- ( - 72 ) \pm 8}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 8}{2 \cdot 10}, x_{2} = \frac{- ( - 72 ) - 8}{2 \cdot 10}

x = \frac{- ( - 72 ) + 8}{2 \cdot 10} : 4

x = \frac{- ( - 72 ) - 8}{2 \cdot 10} : \frac{16}{5}

The solutions to the quadratic equation are:

x = 4, x = \frac{16}{5}

5 x = (2 x + 1)^{2}

- 4.9 t^{2} + 11 t + 500 = 0

- x^{2} - 4 x + 5

\frac{3}{2} x^{2} + \frac{x}{3} + 1 = 0

4 x^{2} + 16 x - 87 = - 3

What are the solutions to the equation x^2-7.2x+12.8=0 ?
The solutions to the equation x^2-7.2x+12.8=0 are x=4,x= 16/5
Find the zeros of x^2-7.2x+12.8=0
The zeros of x^2-7.2x+12.8=0 are x=4,x= 16/5