What are the solutions to the equation ((x-3)^2)/2-x+x^2=x-(x-2) ?

The solutions to the equation ((x-3)^2)/2-x+x^2=x-(x-2) are x= 5/3 ,x=1

Find the zeros of ((x-3)^2)/2-x+x^2=x-(x-2)

The zeros of ((x-3)^2)/2-x+x^2=x-(x-2) are x= 5/3 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{( x - 3 ) ^{2}}{2} - x + x^{2} = x - (x - 2)

x = \frac{5}{3}, x = 1

Decimal Notation

x = 1.66666 \dots, x = 1

Solution steps

\frac{( x - 3 ) ^{2}}{2} - x + x^{2} = x - (x - 2)

Multiply both sides by

2

(x - 3)^{2} - 2 x + 2 x^{2} = 2 x - 2 (x - 2)

Expand

(x - 3)^{2} - 2 x + 2 x^{2} : 3 x^{2} - 8 x + 9

Expand

2 x - 2 (x - 2) : 4

3 x^{2} - 8 x + 9 = 4

Move

4

to the left side

3 x^{2} - 8 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 5 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2}{2 \cdot 3} : \frac{5}{3}

x = \frac{- ( - 8 ) - 2}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = 1

3 c + 10 = 28

3 q - 2 \leq - 10 or 3 q - 2 > 10

4 u^{2} v + 16 u v^{2} + 16 v^{3}

\frac{6 ^{5}}{6 ^{2}}

x^{2} - 18 x + 80

What are the solutions to the equation ((x-3)^2)/2-x+x^2=x-(x-2) ?
The solutions to the equation ((x-3)^2)/2-x+x^2=x-(x-2) are x= 5/3 ,x=1
Find the zeros of ((x-3)^2)/2-x+x^2=x-(x-2)
The zeros of ((x-3)^2)/2-x+x^2=x-(x-2) are x= 5/3 ,x=1