What are the solutions to the equation ax^2+x=7x ?

The solutions to the equation ax^2+x=7x are x= 6/a ,x=0;\quad a\ne 0

Find the zeros of ax^2+x=7x

The zeros of ax^2+x=7x are x= 6/a ,x=0;\quad a\ne 0

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a x^{2} + x = 7 x

x = \frac{6}{a}, x = 0; a \neq = 0

Solution steps

a x^{2} + x = 7 x

Move

7 x

to the left side

a x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 a \cdot 0}{2 a}

(- 6)^{2} - 4 a \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 a}, x_{2} = \frac{- ( - 6 ) - 6}{2 a}

x = \frac{- ( - 6 ) + 6}{2 a} : \frac{6}{a}

x = \frac{- ( - 6 ) - 6}{2 a} : 0

The solutions to the quadratic equation are:

x = \frac{6}{a}, x = 0; a \neq = 0

q^{2} + 10 q + 25 = 0

(x^{2} - x) = 0

x + 2 = x^{2} - 4

64 x^{2} - 128 x = 0

x^{2} - 4 x - 59 = - 28

What are the solutions to the equation ax^2+x=7x ?
The solutions to the equation ax^2+x=7x are x= 6/a ,x=0;\quad a\ne 0
Find the zeros of ax^2+x=7x
The zeros of ax^2+x=7x are x= 6/a ,x=0;\quad a\ne 0