What are the solutions to the equation x^2+2.5x-1.5=0 ?

The solutions to the equation x^2+2.5x-1.5=0 are x= 1/2 ,x=-3

Find the zeros of x^2+2.5x-1.5=0

The zeros of x^2+2.5x-1.5=0 are x= 1/2 ,x=-3

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x^{2} + 2.5 x - 1.5 = 0

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

x^{2} + 2.5 x - 1.5 = 0

Multiply both sides by

10

10 x^{2} + 25 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 10 ( - 15 )}{2 \cdot 10}

2 5^{2} - 4 \cdot 10 (- 15) = 35

x_{1, 2} = \frac{- 25 \pm 35}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 25 + 35}{2 \cdot 10}, x_{2} = \frac{- 25 - 35}{2 \cdot 10}

x = \frac{- 25 + 35}{2 \cdot 10} : \frac{1}{2}

x = \frac{- 25 - 35}{2 \cdot 10} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 3

x^{(2)} + (\frac{x}{4})^{(2)} = 16

(3 x + 1) (x - 2) = 0

4 x^{2} - 16 x - 15 = 3 x^{2} - 24

a^{2} + 14 a - 51 = 0

t^{2} = 10

What are the solutions to the equation x^2+2.5x-1.5=0 ?
The solutions to the equation x^2+2.5x-1.5=0 are x= 1/2 ,x=-3
Find the zeros of x^2+2.5x-1.5=0
The zeros of x^2+2.5x-1.5=0 are x= 1/2 ,x=-3