What are the solutions to the equation -x^2+8x+47=0 ?

The solutions to the equation -x^2+8x+47=0 are x=4-3sqrt(7),x=4+3sqrt(7)

Find the zeros of -x^2+8x+47=0

The zeros of -x^2+8x+47=0 are x=4-3sqrt(7),x=4+3sqrt(7)

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- x^{2} + 8 x + 47 = 0

x = 4 - 37, x = 4 + 37

Decimal Notation

x = - 3.93725 \dots, x = 11.93725 \dots

Solution steps

- x^{2} + 8 x + 47 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 47}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 47 = 67

x_{1, 2} = \frac{- 8 \pm 6 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 6 7}{2 ( - 1 )}, x_{2} = \frac{- 8 - 6 7}{2 ( - 1 )}

x = \frac{- 8 + 6 7}{2 ( - 1 )} : 4 - 37

x = \frac{- 8 - 6 7}{2 ( - 1 )} : 4 + 37

The solutions to the quadratic equation are:

x = 4 - 37, x = 4 + 37

2 x^{2} + (m + 6) = m x

4 x^{2} - 4 x - 3

6 m^{2} + 13 m - 5 = 0

x^{2} + 2.21 x + 1.21 = 0

s^{2} - s + 1

What are the solutions to the equation -x^2+8x+47=0 ?
The solutions to the equation -x^2+8x+47=0 are x=4-3sqrt(7),x=4+3sqrt(7)
Find the zeros of -x^2+8x+47=0
The zeros of -x^2+8x+47=0 are x=4-3sqrt(7),x=4+3sqrt(7)