What are the solutions to the equation x^2+7x=14 ?

The solutions to the equation x^2+7x=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2

Find the zeros of x^2+7x=14

The zeros of x^2+7x=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2

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x^{2} + 7 x = 14

x = \frac{- 7 + 105}{2}, x = \frac{- 7 - 105}{2}

Decimal Notation

x = 1.62347 \dots, x = - 8.62347 \dots

Solution steps

x^{2} + 7 x = 14

Move

14

to the left side

x^{2} + 7 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 14) = 105

x_{1, 2} = \frac{- 7 \pm 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 105}{2 \cdot 1}, x_{2} = \frac{- 7 - 105}{2 \cdot 1}

x = \frac{- 7 + 105}{2 \cdot 1} : \frac{- 7 + 105}{2}

x = \frac{- 7 - 105}{2 \cdot 1} : \frac{- 7 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 105}{2}, x = \frac{- 7 - 105}{2}

s^{2} + 3 s + 2

- 3 - x^{2} = 24

(2 x + 5) (x - 4) = 0

x^{2} + 14 x = - 43

m^{2} - 6 m - 55 = 0

What are the solutions to the equation x^2+7x=14 ?
The solutions to the equation x^2+7x=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2
Find the zeros of x^2+7x=14
The zeros of x^2+7x=14 are x=(-7+sqrt(105))/2 ,x=(-7-sqrt(105))/2