What are the solutions to the equation x^2+15x+16=0 ?

The solutions to the equation x^2+15x+16=0 are x=(-15+sqrt(161))/2 ,x=(-15-sqrt(161))/2

Find the zeros of x^2+15x+16=0

The zeros of x^2+15x+16=0 are x=(-15+sqrt(161))/2 ,x=(-15-sqrt(161))/2

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x^{2} + 15 x + 16 = 0

x = \frac{- 15 + 161}{2}, x = \frac{- 15 - 161}{2}

Decimal Notation

x = - 1.15571 \dots, x = - 13.84428 \dots

Solution steps

x^{2} + 15 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 16 = 161

x_{1, 2} = \frac{- 15 \pm 161}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 161}{2 \cdot 1}, x_{2} = \frac{- 15 - 161}{2 \cdot 1}

x = \frac{- 15 + 161}{2 \cdot 1} : \frac{- 15 + 161}{2}

x = \frac{- 15 - 161}{2 \cdot 1} : \frac{- 15 - 161}{2}

The solutions to the quadratic equation are:

x = \frac{- 15 + 161}{2}, x = \frac{- 15 - 161}{2}

x, x^{2} + 2 x - 15 = 0

x, x^{2} y + 4 x y - x^{2} + x + 4 y - 6 = 0

\frac{3 x ^{2}}{4} - 3 = 0

4 m^{2} + 4 m + 17 = 0

2 x^{2} - 3 x = 8

What are the solutions to the equation x^2+15x+16=0 ?
The solutions to the equation x^2+15x+16=0 are x=(-15+sqrt(161))/2 ,x=(-15-sqrt(161))/2
Find the zeros of x^2+15x+16=0
The zeros of x^2+15x+16=0 are x=(-15+sqrt(161))/2 ,x=(-15-sqrt(161))/2