What are the solutions to the equation x^2-51=-2x ?

The solutions to the equation x^2-51=-2x are x=-1+2sqrt(13),x=-1-2sqrt(13)

Find the zeros of x^2-51=-2x

The zeros of x^2-51=-2x are x=-1+2sqrt(13),x=-1-2sqrt(13)

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x^{2} - 51 = - 2 x

x = - 1 + 213, x = - 1 - 213

Decimal Notation

x = 6.21110 \dots, x = - 8.21110 \dots

Solution steps

x^{2} - 51 = - 2 x

Move

2 x

to the left side

x^{2} - 51 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 51 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 51) = 413

x_{1, 2} = \frac{- 2 \pm 4 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 13}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 13}{2 \cdot 1}

x = \frac{- 2 + 4 13}{2 \cdot 1} : - 1 + 213

x = \frac{- 2 - 4 13}{2 \cdot 1} : - 1 - 213

The solutions to the quadratic equation are:

x = - 1 + 213, x = - 1 - 213

4 - x^{2} = \frac{1}{4} + x^{2}

- 4 = x^{2} - 4 x

6 x^{2} + 8 x

x^{2} + x - \frac{1}{4} = 0

r^{2} + r + 6 = 0

What are the solutions to the equation x^2-51=-2x ?
The solutions to the equation x^2-51=-2x are x=-1+2sqrt(13),x=-1-2sqrt(13)
Find the zeros of x^2-51=-2x
The zeros of x^2-51=-2x are x=-1+2sqrt(13),x=-1-2sqrt(13)