What are the solutions to the equation x^2-7x+7=5x+8 ?

The solutions to the equation x^2-7x+7=5x+8 are x=6+sqrt(37),x=6-sqrt(37)

Find the zeros of x^2-7x+7=5x+8

The zeros of x^2-7x+7=5x+8 are x=6+sqrt(37),x=6-sqrt(37)

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x^{2} - 7 x + 7 = 5 x + 8

x = 6 + 37, x = 6 - 37

Decimal Notation

x = 12.08276 \dots, x = - 0.08276 \dots

Solution steps

x^{2} - 7 x + 7 = 5 x + 8

Move

8

to the left side

x^{2} - 7 x - 1 = 5 x

Move

5 x

to the left side

x^{2} - 12 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 1) = 237

x_{1, 2} = \frac{- ( - 12 ) \pm 2 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 37}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 37}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 37}{2 \cdot 1} : 6 + 37

x = \frac{- ( - 12 ) - 2 37}{2 \cdot 1} : 6 - 37

The solutions to the quadratic equation are:

x = 6 + 37, x = 6 - 37

2 x (x - 4) = - 3

6 x (x + 5) = 0

3 x^{2} - 12 x - 1 = 0

x^{2} - 16 x + 32 = 0

45 x^{2} + 5 = 0

What are the solutions to the equation x^2-7x+7=5x+8 ?
The solutions to the equation x^2-7x+7=5x+8 are x=6+sqrt(37),x=6-sqrt(37)
Find the zeros of x^2-7x+7=5x+8
The zeros of x^2-7x+7=5x+8 are x=6+sqrt(37),x=6-sqrt(37)