What are the solutions to the equation -9x^2+9x-1=0 ?

The solutions to the equation -9x^2+9x-1=0 are x=(3-sqrt(5))/6 ,x=(3+sqrt(5))/6

Find the zeros of -9x^2+9x-1=0

The zeros of -9x^2+9x-1=0 are x=(3-sqrt(5))/6 ,x=(3+sqrt(5))/6

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- 9 x^{2} + 9 x - 1 = 0

x = \frac{3 - 5}{6}, x = \frac{3 + 5}{6}

Decimal Notation

x = 0.12732 \dots, x = 0.87267 \dots

Solution steps

- 9 x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 9 ) ( - 1 )}{2 ( - 9 )}

9^{2} - 4 (- 9) (- 1) = 35

x_{1, 2} = \frac{- 9 \pm 3 5}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 9 + 3 5}{2 ( - 9 )}, x_{2} = \frac{- 9 - 3 5}{2 ( - 9 )}

x = \frac{- 9 + 3 5}{2 ( - 9 )} : \frac{3 - 5}{6}

x = \frac{- 9 - 3 5}{2 ( - 9 )} : \frac{3 + 5}{6}

The solutions to the quadratic equation are:

x = \frac{3 - 5}{6}, x = \frac{3 + 5}{6}

2 x^{2} = 96

x^{2} - 11 x + 37 = 0

(x - 2)^{2} + (x + 3)^{2} = 25

x^{2} - 5 x = 0

(- \frac{3}{4})^{2} + y^{2} = 1

What are the solutions to the equation -9x^2+9x-1=0 ?
The solutions to the equation -9x^2+9x-1=0 are x=(3-sqrt(5))/6 ,x=(3+sqrt(5))/6
Find the zeros of -9x^2+9x-1=0
The zeros of -9x^2+9x-1=0 are x=(3-sqrt(5))/6 ,x=(3+sqrt(5))/6