What are the solutions to the equation -3x^2-42x-51=-12x ?

The solutions to the equation -3x^2-42x-51=-12x are x=-5-2sqrt(2),x=-5+2sqrt(2)

Find the zeros of -3x^2-42x-51=-12x

The zeros of -3x^2-42x-51=-12x are x=-5-2sqrt(2),x=-5+2sqrt(2)

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- 3 x^{2} - 42 x - 51 = - 12 x

x = - 5 - 22, x = - 5 + 22

Decimal Notation

x = - 7.82842 \dots, x = - 2.17157 \dots

Solution steps

- 3 x^{2} - 42 x - 51 = - 12 x

Move

12 x

to the left side

- 3 x^{2} - 30 x - 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 ( - 3 ) ( - 51 )}{2 ( - 3 )}

(- 30)^{2} - 4 (- 3) (- 51) = 122

x_{1, 2} = \frac{- ( - 30 ) \pm 12 2}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 12 2}{2 ( - 3 )}, x_{2} = \frac{- ( - 30 ) - 12 2}{2 ( - 3 )}

x = \frac{- ( - 30 ) + 12 2}{2 ( - 3 )} : - 5 - 22

x = \frac{- ( - 30 ) - 12 2}{2 ( - 3 )} : - 5 + 22

The solutions to the quadratic equation are:

x = - 5 - 22, x = - 5 + 22

s^{2} + 5 s + 8

x (22 - x) = 105

2^{2} + (- 3^{2}) = c^{2}

1 0^{2} + y^{2} = 9^{2}

12 - 8 x + x^{2} = 0

What are the solutions to the equation -3x^2-42x-51=-12x ?
The solutions to the equation -3x^2-42x-51=-12x are x=-5-2sqrt(2),x=-5+2sqrt(2)
Find the zeros of -3x^2-42x-51=-12x
The zeros of -3x^2-42x-51=-12x are x=-5-2sqrt(2),x=-5+2sqrt(2)