What are the solutions to the equation 0=x^2-x-20 ?

The solutions to the equation 0=x^2-x-20 are x=5,x=-4

Find the zeros of 0=x^2-x-20

The zeros of 0=x^2-x-20 are x=5,x=-4

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0 = x^{2} - x - 20

x = 5, x = - 4

Solution steps

0 = x^{2} - x - 20

Switch sides

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

(x + 2)^{2} - 3 x = 24

y^{2} - 18 y + 81 = 0

x^{2} - 10 x - 47 = - 8

4 a^{2} + 12 a + 5 = 0

92 = 2 + 10 c^{2}

What are the solutions to the equation 0=x^2-x-20 ?
The solutions to the equation 0=x^2-x-20 are x=5,x=-4
Find the zeros of 0=x^2-x-20
The zeros of 0=x^2-x-20 are x=5,x=-4