What are the solutions to the equation (x^2+4x+2)=0 ?

The solutions to the equation (x^2+4x+2)=0 are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of (x^2+4x+2)=0

The zeros of (x^2+4x+2)=0 are x=-2+sqrt(2),x=-2-sqrt(2)

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(x^{2} + 4 x + 2) = 0

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

(x^{2} + 4 x + 2) = 0

Refine

x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2}{2 \cdot 1}

x = \frac{- 4 + 2 2}{2 \cdot 1} : - 2 + 2

x = \frac{- 4 - 2 2}{2 \cdot 1} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

y, x^{(3)} + 3 x y + y^{(2)} = 5

s^{2} + 5 = 0

- 2 x^{2} - 12 x - 18 = 0

y, \frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

x^{2} + 23 x - 72 = 0

What are the solutions to the equation (x^2+4x+2)=0 ?
The solutions to the equation (x^2+4x+2)=0 are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of (x^2+4x+2)=0
The zeros of (x^2+4x+2)=0 are x=-2+sqrt(2),x=-2-sqrt(2)