What are the solutions to the equation a^2+4a-12=0 ?

The solutions to the equation a^2+4a-12=0 are a=2,a=-6

Find the zeros of a^2+4a-12=0

The zeros of a^2+4a-12=0 are a=2,a=-6

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a^{2} + 4 a - 12 = 0

a = 2, a = - 6

Solution steps

a^{2} + 4 a - 12 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

a_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 4 + 8}{2 \cdot 1}, a_{2} = \frac{- 4 - 8}{2 \cdot 1}

a = \frac{- 4 + 8}{2 \cdot 1} : 2

a = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

a = 2, a = - 6

c = 0.05 x^{2} - 5 x + 500

6^{2} + 7^{2} = x^{2}

2 x^{2} - 12 x + 7

2 s^{2} + s + 2

x^{2} + \frac{15}{4} = \frac{3 x ^{2} - x + 3}{4} + 3

What are the solutions to the equation a^2+4a-12=0 ?
The solutions to the equation a^2+4a-12=0 are a=2,a=-6
Find the zeros of a^2+4a-12=0
The zeros of a^2+4a-12=0 are a=2,a=-6